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Find the area of a trapezoid with a height of 4 m and bases of 12 m and 19 m.
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A=(h/2)(B1+B2) just plug in
like this A = 1/2h(b1 + b2) Now multiply both sides by 2 to remove the fraction on the right: 2A = h(b1 + b2) Now divide both sides by h: 2A/h = b1 + b2 Now substract b2 from both sides: 2A/h - b2 = b1
is that good
can someone tell if i did this good
sorry,was busy: u want 2 find A so A=(4/2)(12+19)=2(31)=62 m^2
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thank i did it
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