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Mathematics 30 Online
OpenStudy (rayford):

sqrt64/sqrt3

OpenStudy (ganpat):

\[\sqrt{64} / \sqrt{3} = \sqrt{(8 * 8)} / \sqrt{3} = 8/\sqrt{3}..\]

OpenStudy (rayford):

oh my god it's so easy now that you explained it!...may you answer one more?

OpenStudy (ganpat):

ya sure..

OpenStudy (ganpat):

its good, if u practice as well :D

OpenStudy (rayford):

sqrt10(4-sqrt5)+sqrt8(sqrt5+2)

sam (.sam.):

\[ 8/\sqrt{3}~~ \text{is \not the simplified form yet}\]

OpenStudy (dls):

8/root 3 = 8 root 3/3=> 13.856/3=>4.61

OpenStudy (anonymous):

yes, 8/ sqrt of 3 is not yet simplified, you need to raionalize it.

OpenStudy (rayford):

so is it 8sqrt3/3?

OpenStudy (dls):

Its 4.61

OpenStudy (ganpat):

\[\sqrt{10} * (4 - \sqrt{5}) + \sqrt{8} * (\sqrt{5} + 2) = \] \[4\sqrt{10} - \sqrt{(5 * 10)} + \sqrt{(5 * 8)} + 2\sqrt{8}\] Now can u solve further...

OpenStudy (rayford):

wait guys ..for the first one the answer choices are..8sqt3/3 8/3 8/sqrt3 sqrt3/3

OpenStudy (dls):

8sqt3/3 !

OpenStudy (ganpat):

for the second one... \[4\sqrt{10} - 5\sqrt{2} + 2\sqrt{10} + 4\sqrt{2} = 6\sqrt{2} - \sqrt{2}\] is the answer...

OpenStudy (rayford):

the second question choices are..4sqrt10-sqrt50+sqrt40+2sqrt8 6sqrt10-sqrt50+2sqrt8 2sqrt8-4 6sqrt10-sqrt2

OpenStudy (ganpat):

sorry last one.. typo error..

OpenStudy (rayford):

thank you...now i can sleep..3;40 am and i can finally sleep...enjoy ur 2 medals.

OpenStudy (ganpat):

lol !! have a good sleep :) good night !!

OpenStudy (theviper):

\[\Huge{\color{red}{\sqrt{64}\over \sqrt{3}}}\]\[\LARGE{\color{blue}{{8\over \sqrt{3}}=\frac{8}{1.714}}}\]

OpenStudy (anonymous):

8/sqrt3

OpenStudy (theviper):

yes right @muhammad9t5 but it is equal to 8/1.714 :)

OpenStudy (anonymous):

yes for further solving your asnwer is also right. but in math we need only whole numbers.

OpenStudy (theviper):

;)

OpenStudy (anonymous):

friend also rate me please.

OpenStudy (theviper):

k I m ur fan :)

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