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If ( tan(A-B)/tan A )+ Sin**2 C/sin**2 A), then prove that tanA tanB = tan**2 c
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can you retype the problem? not that clear here, sorry. :(
yeah sure
yeah sure \[(\tan(A+B)/\tan A) + \sin ^{2}C/\sin ^{2}A \] then prove that \[(\tan A )(\tan B)=\tan ^{2}C\]
working on it.
thanx
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i think you are missing an equal sign in the first expression... if "equation" is true, then prove this equation holds
i think so, can you clarify that part?
@jainilk.... pls clarify....
yeah sorry RHS in first equation is 1
tan(A-B)/tan A )+ Sin**2 C/sin**2 A \[\huge \frac{tan(A-B)}{tan A }+\frac{sin^2C}{sin^2A}=1 \] like that?
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yeah
I think it is question based on triangle properties where: \(A + B + C = 180^{\circ}\)
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