Question

(x-2)^+(x-2)-12=0 solve using an appropriate technique????

Answer 1

x^2-4x+4+x-2-12
=x^2-3x-10=0
=x^2-5x+2x-10=0
(x-5)(x+2)=0
x=5
x=-2

Answer 2

sai1234 you are awesome thank you.

Answer 3

(x-2)^2 +(x-2) -  12 =0
Let y= x-2 substituting we get
Y ^2 + Y -12 = 0
Y^2 + 4 Y - 3Y -12 = 0
Y( Y + 4) -3(Y+ 4)= 0
(Y+ 4)(Y-3)=0
x-2+4= 0, x-2-3=5
X=-2, x= 10

Answer 4

Sorry it is x-2-3=0
X= 5

Answer 5

This is the substituting technique to solve it in a simple manner