Question

see the attached image file

Answer 1

intx+6 - int x^2 on the bounds given

Answer 2

\[\int\limits_{0}^{2}((x+6)-(x ^{2}))dx\]

Answer 3

Bounded integrals, I believe the general concept is you find the area beneath the top curve over the interval, the area beneath the bottom curve over the interval, and because you want the area below the top curve and above the bottom curve, you then subtract the first function from the second function, and find the integral over the interval...

Answer 4

Like @nitz has done

Answer 5

1/2*x^2 +6x - 1/3x^3 then do the bounds

Answer 6

and @zzr0ck3r rockin' it