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1/y-2=2/y+1
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cross multiply: 2(y-2) = 1(y+1) can you proceed from there?
5?
That's correct.
how do i know if it has an extraneous root
Do i put the 5 in place of the y's
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If you plug your solution back in for y only to find that it does not work. In this case it has an extraneous root.
For this problem, you will see that you arrive at 6 = 6. This is true, so there are no extraneous roots.
Okay :) Thanks for your help!
@qpHalcy0n how would you set up this question: 5/(2x+6) - 2= (1-8x)/4x ?
You can split the right side up to look like: \[1/4x - 8x/4x = 1/4x - 2\] This should get you on the right track.
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