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(2+2i)^4
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\[(x+y)^4=(x+y)^2 (x+y)^2=(x^2+2xy+y^2)(x^2+2xy+y^2)\\=x^2(x^2+2xy+y^2)+2xy(x^2+2xy+y^2)+y^2(x^2+2xy+y^2)\\=x^4+4x^3y+6x^2y^2+4xy^3+y^4\] let x=2 and y=2i to get ur answer
this is a question i must answer with eulers formula. I get it to squr8(cos(45)+isin(45) but I cant get it right. answer is -64 btw
oh...let me try again
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