Question

Circle A has an equation of (x + 8)2 + (y + 3)2 = 16. Where is the center of the circle located?

in the first quadrant

on the y-axis

on the x-axis

in the third quadrant

Answer 1

in the third quadrant

Answer 2

(-8,-3)

Answer 3

@JahEmpress did you understand it?

Answer 4

ummm no not really..

Answer 5

Do you know why (-8,-3) is the center?

Answer 6

The canonical equation of a circle of center (a,b) and radius r is
\[
(x-a)^2 + (y-b)^2 = r^2

\]

Answer 7

ohhh ok , i" think" i might how..

Answer 8

but thanks tho