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Help please, giving it in the form k root 2
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\[2^{\frac{-3}{2}} + 2^{\frac{-1}{2}} +2^{\frac{1}{2}} + 2^{\frac{3}{2}}\]
@waterineyes
-2/2 is how much??
remember: \[\huge \color{green}{x^{\frac{a}{b}} = \sqrt[b]{x^a}}\]
\[(1/2)^{3/2}+(1/2)^{1/2}+(2)^{1/2}+(2)^{3/2}\]
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What is the first term @zaphod is it -3/2 or -2/2 ??? and last term also..
-3/2
Okay...
last term is 3/2
|dw:1342951837951:dw|
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