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Integrate: Mainly interested in the steps involved, as opposed to the answer, so steps involved would be great. Thanks in advance. (1-3x^2)/x dx
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\[\int\limits_{-}^{-} \frac{1-3x^2}{x}\]
use substitution let u=1-3x^2 then du=-6xdx can u do this
brake it up into two fractions
\[ \int \frac{1}{x} - \frac{3x^2}{x}dx\]
you should be able to do it now :)
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This helps a lot, thank you. :)
np.
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