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log(x+5)-log(x-3)=log5 want to get checked! logx-3/x+5=log5 drop the log . x-3/x+5=5 (x+5)*(x-3/x+5)=5(x+5) x-3=5x+25 -28=4x x=-7
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consider - to be under
- log(n) = /n in the setup
logx-3/x+5=log5 Is this step correct?
Just check it by inputting the following into the calculator. \( \color{Black}{\Rightarrow (\log (-7) + 5) - (\log(-7) - 3)}\) and \(\log5\) Check if they give the same result.
I think it should have been logx+5/x-3=log5
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make sure it's non negative too.
\( \color{Black}{\Rightarrow \log(-2) - \log(-10) = ?}\)
Doesn't look like we have a definite number ;)
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