Algebra 1, please help me :)
Create your own quadratic equation that has an axis of symmetry of x = −1 and whose graph opens down. Then find the vertex, domain, range, and x-intercepts. Show all work to receive full credit.

Question

Algebra 1, please help me :)
Create your own quadratic equation that has an axis of symmetry of x = −1 and whose graph opens down. Then find the vertex, domain, range, and x-intercepts. Show all work to receive full credit.

anonymous · Answer

cant understand is there any graph??

anonymous · Answer

No graph...

anonymous · Answer

Random graph. Formula for the axis of symmetry:
$$x = -\frac {b}{2a}$$$$x = -1$$$$-1 = -\frac b{2a}$$
$$y = -x^2 - 2x - 1$$Vertex: (-1, 0)
Domain: All real numbers
Range: y ≤ 0
x - intercepts:
$$y = -x^2 - 2x - 1$$$$0 = -x^2 - 2x - 1$$$$0 = x^2 + 2x + 1$$$$0 = (x + 1)(x + 1)$$\[x = -1