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find the range of the quadratic function. f(x) = (x+8)^2 - 7
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I think it is (-infinity, -7)
No...
do i factor it out and find the maximum
Put f(x) = y first: \[y = (x+8)^2 - 7\] \[(x+8)^2 = y + 7\] \[x + 8 = \sqrt{y + 7} \implies x = \sqrt{y + 7} - 8\]
What values y cannot take??
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Number inside the square root must not be negative.. So: \[y + 7 \ge 0\] Can you solve now??
Subtract both the sides by 7 and tell me what do you get??
-7
so is it (-7, infinity)
Yes...
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thank you again
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