Question

Determine the values of sin 2θ, cos 2θ, and tan 2θ, given tanθ = -7/24, and π/2 ≤ θ ≤ π.

Answer 1

@apoorvk

Answer 2

Use them:

\[\sin2x = \frac{2tanx}{1 + \tan^2x}\]

\[\cos2x = \frac{1 -\tan^2 x}{1 + \tan^2 x}\]

Answer 3

how did you come up with those ? :S
we're supposed to used double angle formulase

Answer 4

Your sine value and tan value are wrong in denominator I guess @apoorvk

Answer 5

\[\tan2x = \frac{2tanx}{1 - \tan^2x}\]

Answer 6

Sorry for the error!

Answer 7

It is okay I am just reminding you ..

Answer 8

are these double angle ?

Answer 9

Yes they are..
Left hand side you have 2x and right hand side you have x..

Answer 10

you have given the value of tanx, you have to just plug in that value in place of tanx in the formulas..