Question

Find the x and y

Answer 1

so i got X wrong \[8\sqrt{3}\]
and
Y i got this right \[4\sqrt{6}\]

Answer 2

since the hypotenuse of the 45-45-90 triangle is 8, then one of it's sides must be \(\large 8(\frac{\sqrt2}{2})= \) ????

Answer 3

5.65 or 5.66?

Answer 4

for x:
sin 45 = opp/hyp
sine 45 = opp/8
opp = 8sin45
= 8*1/root 2
=\[4\sqrt{2}\]
\[x= 4\sqrt{2} /sine30\]
\[x = 4\sqrt{2} /0.5\]
\[x = 8\sqrt{2}\]