Quadrilaterals and Polygons
Did you try it? @Trexy
Find the side lengths: 1) (0, 3) and (3, 0) 2) (3, 0) and (0, -3) 3) (0, -3) and (-3, 0) 4) (-3, 0) and (0, 3) Check if they are equal! Next find the slopes of each sides
@Trexy are you here?
Hey @ash2326 Im back.. So far I got the Slope: AB=-1 BC=1 CD=-1 AD=1 and next i got the distance formula: AB=4.24 BC=4.24 CD=4.24 AD=4.24 sORRY FOR THE LATE REPLY..
and its SQUARE Im guessing perimeter is 16.96? Im not sure how to do area for this? Please
to do area find the length of 2 sides using the distance formula
like how @timo86m ?
if you know for sure it is a square then just find 2 sides perpendicular and use the distance formula to find the 2 sides.
ok so its 17.9776 right?
@timo86m and @Calcmathlete please?
is that what you drew?
top half lol
here timo
it 18 i think i uploading pic
oh wait that is area lol
18
@Trexy we found all the sides are equal and AB and BC are perpendicular to each other ( slopes product is -1) if we check all the adjacent sides are perpendicular to each other so this is a square
perimeter is sqrt(18)*4=16.970562
Area of square= a^2 Perimeter= 4 \times side length
hw did you get that, cuz my dad is asking, since i got \[4.24\times4.24=17.977\] or its actually the same ?
\[\sqrt {18}=4.24\] But it's mot exact , your area will be exact that's 18
*not
since area of square = a^2 and one side is sqrt(18) then (sqrt(18))^2=18 :)
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