Question

ans. the following:
x^2-2x=3
x^2-12x=64
4x^2+4x-24=0
9x^2-12x-5=0
16x^2-8x=15

Answer 1

wha we hv to find??

Answer 2

Every equation can be solved by the formula\[\Huge{\color{red}{-b \pm \sqrt{b^2-4ac}\over2a}}\]

Answer 3

Equations 1 is as follows:-
\[1.)x^2-2x-3=0\]

Answer 4

here b=-2, a=1, c=-3

Answer 5

what is the ans.?

Answer 6

for the first 1...x = 7 or -9

Answer 7

@florrdeliza dont ask for answer directly...solve it urself...it will help u a lot..

Answer 8

x^2-12x-64=0
x^2-16x+4x-64=0
x(x-16)+4(x-16)=0
(x+4)(x-16)=0
x=-4 or x=16

Answer 9

4x^2+4x-24=0
4x^2+12x-8x-24=0
4x(x+3)-8(x+3)=0
(4x-8)(x+3)=0
x=2 or x=-3

Answer 10

excusme i am solving your problems..........atleast see them.........