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Mathematics 9 Online
OpenStudy (anonymous):

Determine the type and number of solutions of 3x^2+6x+4=0

OpenStudy (anonymous):

has two solutions because Quadratic (highest power of x is 2) for ax^2+bx+=0 the discriminant is b^2-4ac so discriminant is 6^2-4(3)(4)=-12 since discriminant is negative roots must be imaginary and unequal

OpenStudy (anonymous):

ax^2+bx+c*=0

OpenStudy (anonymous):

did u get it? @Mekorte

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