I'm really lost on this one. Can someone show me where to start..?
Type the equation of the given line in standard form.
The line through (2, -1) and parallel to x - 2y = 6.
Thanks so much!
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OpenStudy (anonymous):
use point slope form of a line
(y+1) = 1/2(x-2)
OpenStudy (anonymous):
parallel means same vector defins the line. So use <1,-2>.
(x-2)-2(y+1)=0
x-2-2y-2=0
x-2y=4
OpenStudy (anonymous):
@A.Avinash_Goutham
Okay, so here it is..
(-1+1)=(1/2)(2-2)
0=(1/2)0
0=0
What did I do wrong?
OpenStudy (anonymous):
x - 2y = 6.
this is already standart form. So just use it.....
OpenStudy (anonymous):
why you go to slope form first?
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OpenStudy (anonymous):
@myko
which equation is that? Like the beginning equation to where I substitute.
OpenStudy (anonymous):
u kno that's the eqn...like u need not plg in those values.....jus simplify it to get the eqn nd u get 0=0 coz the point satisfies the line.........
OpenStudy (anonymous):
yes, just put 0 at the right side
OpenStudy (anonymous):
@myko but which equation did you originally use?
OpenStudy (anonymous):
x - 2y = 6
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