Question

I'm really lost on this one. Can someone show me where to start..?

Type the equation of the given line in standard form.
The line through (2, -1) and parallel to x - 2y = 6.

Thanks so much!

Answer 1

use point slope form of a line
(y+1) = 1/2(x-2)

Answer 2

parallel means same vector defins the line. So use <1,-2>.
(x-2)-2(y+1)=0
x-2-2y-2=0
x-2y=4

Answer 3

@A.Avinash_Goutham
Okay, so here it is..
(-1+1)=(1/2)(2-2)
0=(1/2)0
0=0
What did I do wrong?

Answer 4

x - 2y = 6.
this is already standart form. So just use it.....

Answer 5

why you go to slope form first?

Answer 6

@myko
which equation is that? Like the beginning equation to where I substitute.

Answer 7

u kno that's the eqn...like u need not plg in those values.....jus simplify it to get the eqn nd u get 0=0 coz the point satisfies the line.........

Answer 8

yes, just put 0 at the right side

Answer 9

@myko but which equation did you originally use?

Answer 10

x - 2y = 6

Answer 11

@myko Ohh! I see now. Thanks :)

Answer 12

yw