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By pedaling, you turn the large gear through an angle of 60°. AD = 5 inches, and BC = 3 inches. CD, the length of the chain between the gears, is 17 inches. How far does the chain move around the circumference of the larger gear to the nearest tenth of an inch? Enter only the number. (Hint: First find the circumference of the large gear. Then find the arc of the circumference cut by a central angle of 60°.)

Question

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By pedaling, you turn the large gear through an angle of 60°. AD = 5 inches, and BC = 3 inches. CD, the length of the chain between the gears, is 17 inches. How far does the chain move around the circumference of the larger gear to the nearest tenth of an inch? Enter  only the number. (Hint: First find the circumference of the large gear. Then find the arc of the circumference cut by a central angle of 60°.)

anonymous · Answer

I need this answer quick! plz help!