Question

I need some assistance with this word problem please.

The length of a rectangle is 3yd more than twice its width, and the area of the rectangle is 35^2. Find the dimensions of the rectangle.

Answer 1

let
length = l
width = w

Answer 2

The length of a rectangle is 3yd more than twice its width

=>


l = 2w + 3

Answer 3

area of the rectangle is 35

=>

area = l*w

=>

35 = l * w
35 = (2w+3)w
35 = 2w^2 + 3w
2w^2+3w-35 = 0

Answer 4

you can solve the quadratic equation for w ?

Answer 5

i think so ..I am so not sure of myself anymore :(

Answer 6

hmm

Answer 7

-35+3w+2w^2 +0
(-5-1)(7-2)=0
Is this right so far?

Answer 8

(-5-1w)(7-2w) i mean

Answer 9

yes !!

Answer 10

so w = 7/2

Answer 11

find what l is

Answer 12

3.5

Answer 13

would be the decimal right?

Answer 14

yes 3.5 is good :P

Answer 15

L would be 10?

Answer 16

cause you have the 2(3.5) +3 +10

Answer 17

correct ! very good work :)

Answer 18

thank you! you are an awesome teacher

Answer 19

np... yw:))