tell me the way how to solve it througly : 1.2*10<2*2.8*10<4/4*1.4
That's arithmetic D:
i'am weak in this area.
and the answer is : \[6\times10<7 m\]
Can you rewrite it properly.. what is dot(.) means there in between 2*2.8*10 ??
Use equation editor or draw tool to write that..
this one.what i was asking. i know it answer. but hav'nt understood how this calculation takes place plesae helppp
And what you have written there is totally different..
yes. i hav'nt used the editor well. now please tell me
Cancel the terms 1 by 1..
can u please use the equation editor to tell me please.?
Yes I will..
\[\large \frac{1.2 \times 10^{-2} \times 0.28 \times 10^{-3}}{4 \times 1.4}\]
now what to do?
See 1.2 can be written as: \(\frac{1}{2}\) 0.28 can be as: \(\frac{28}{100}\) 1.4 can be as : \(\frac{14}{10}\) \(10^{-2}\) can be : \( \frac{1}{100}\) \(10^{-3}\) can be : \( \frac{1}{1000}\)
Sorry mistake there: 1.2 can be written as : \(\frac{12}{10}\)
is the denominator as zero is given according to the inverse given?
No...
In case of multiplication when you cancel any terms then result is 1 not 0..
then how you have putten the zero's in dnominator?
See in case of decimals: \[x.y = \frac{xy}{10}\] After dot there is one term so we put 10 in denominator.. Getting??
& if there is x.2y then is that be =x2y/100 ?
similary: for: \[x.yz = \frac{xyz}{100}\] There is yz after dot so we will put 100..
Yes absolutely correct..
okay.thanks. now how shall we contineu?
Yes..
And remember: \[\large x^{-a} = \frac{1}{x^a}\] this is the case with \(10^{-2}\) and \(10^{-3}\) Getting??
So what we get I show you after putting...
1/10squr. and 1/10cube?
\[\large \implies \frac{\frac{12}{10} \times \frac{1}{100} \times \frac{28}{100} \times \frac{1}{1000}}{4 \times \frac{14}{10}}\] Getting??
yes..now please contineu
See now you can bring 10 0r 100 or 1000 which are in numerator to the denominator and which are in denominator can be brought back to numerator.. Like this: \[\large \implies \frac{12 \times 28 \times 10}{ 10 \times 100 \times 100 \times 1000 \times 4 \times 14}\]
which terms from denumerator are placed in numeraor?
10..
there is 14/10 so bring the 10 above see I have multiplied in the last in the numerator.. Getting??
we will leave 4 and 14 still on denom.. tr?
@waterineyes
Cancel what ever is being cancelled: \[\large \implies \frac{6 \times \cancel{10}}{10000000 \cancel0} \implies \frac{6}{10000000}\]
See the terms that are denominator of denominator can be brought to numerator..
in denominator 10 is again denominator so bring it up..
Or you can remember it as: \[\large \frac{\frac{a}{b}}{\frac{c}{d}} = \frac{a \times d}{b \times c}\]
how u brought 6/10000000
Now back: \[\implies \frac{6}{10000000} \implies \frac{6}{10^7}\]
you got its previous step of not?? \[\implies \frac{6 \times 10}{100000000}\] Is it clear to you??
yes. but how it came?
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