Can Someone tell me how we use the formula y=mx+b
its the point slope form of a straight line on the number plane m = slope and b = y intercept... ( where the line cuts the y axis) e.g. y = 3x + 5 slope 3 and y intercept y = 5 y = 11 - 2x slope -2 and y intercept y =11
What is rise/run then?
you use it for linear equations m is the slope and b is the y intercept you use the equation to find out x and y
when do we use y=mx+b compared to rise/run
rise/run = whe your plooting points in a graph
rise over run is used to find m only
then when we are asked to find the slope what do we use ?
so say if its 2/3... ur rise 2 and go right 3.... its used to fing slope as cambell said
what is the prupose of y=mx+b then ?
ok... can you draw the line y = 2x - 3
no
ok... I think you need to learn a little substitution algebra
Find the equation of the straight line that has slope m = 4 and passes through the point (–1, –6). Okay, they've given me the value of the slope; in this case, m = 4. Also, in giving me a point on the line, they have given me an x-value and a y-value for this line: x = –1 and y = –6. In the slope-intercept form of a straight line, I have y, m, x, and b. So the only thing I don't have so far is a value for is b (which gives me the y-intercept). Then all I need to do is plug in what they gave me for the slope and the x and y from this particular point, and then solve for b: y = mx + b (–6) = (4)(–1) + b –6 = –4 + b –2 = b Then the line equation must be "y = 4x – 2".
Oh, so y=mx+b is an equation to bascially find everything about a line where as riseérun is the slope which can be used in the equation to find other values right?
and if you were to graph this, you would start at -2 and you would go up 4 over up 4 and over and so on
correct
So when A question shows me a line and I need to find the slpoe I use rise/run and when i need to make an equation i use y=mx+B
thats it...
Thanks!
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