Question

The perimeter of a rectangle is 34yd, and the area of the rectangle is 64yd^2 . Find the dimensions of the rectangle.

Can anyone help me please.

Answer 1

\[P=2(x+y)\]

Answer 2

\[2(x+y)=34\]
\[A=xy=64\]
solve simultaneously

Answer 3

\[xy=64\]
\[x+y=17\]

Answer 4

can you solve simultaneously

Answer 5

how did you get the 17?

Answer 6

2 divided into the 34 right

Answer 7

w=16 and L=18?

Answer 8

yes 34/2=17

Answer 9

it is 60yd^2 not 64yd^2