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youre going to want to cross multiply and work out the quadratic
err, it aint quadratic, its linear ... so its even better
oh ok
thats the usual method tho, cross then solve another idea tho is this: \[\frac{30}y=\frac{55}{y+5}\] \[\frac{y+5}y=\frac{55}{30}\] \[\frac yy+\frac5y=\frac{55}{30}\] \[1+\frac5y=\frac{55}{30}\] \[\frac5y=\frac{55}{30}-\frac{30}{30}\] \[\frac1y=\frac15(\frac{55}{30}-\frac{30}{30})\] then flip the results :)
with any luck, y=6
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thats right! thanks!
yw
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