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determine the sum or difference in clock 12 arithmetic. (7+10) + (8+7) A.7 B.8 C.32 D.2
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add up (7+10) + (8+7) to get ???
32?
good, now divide that into 12 32/12 = ??? remainder ???
2.6 ? so the answer is 2...?
Similar example: 40/12 = 3 remainder 4 This is because 40 goes into 12 three whole times and has 4 left over
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good so far
but you're not quite done yet
take that decimal part 0.6 and multiply it by 12 to get the remainder
it should be 0.6667 btw
it was. & i got 7.2 !
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it should be more like 0.667*12 = 8.004, which is close to 8 So 32/12 = 2 remainder 8
ok.. so my answer is B.8 ...?
yes
Since "mod" deals with remainders
thankyou!!
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you're welcome
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