Question

solve the equation
(3tan^2x-1)(tan^2x-3)=0

Answer 1

Put separately equal to 0..
\[3\tan^2x-1 = 0\]

\[\tan^2x-3 = 0\]

Answer 2

Now find tanx by taking square root..

Answer 3

you need to solve

\[3\tan^2(x) -1 = 0\]

and

\[\tan^2(x) - 3 = 0\]

looking at the 1st equation

\[\tan^2(x) = \frac{1}{3}\]

take the square root of both sides

the 2nd equation

\[\tan^2(x) = 3\]

take the square root of both sides...

Answer 4

this will give 4 solutions... 2 for each equation.