Question

Evaluate b^2c^-1 for b = 8 and c = -4.
i got 256.. is that right?

Answer 1

Check once again..

Answer 2

this is

\[(8)^2\times \frac{1}{-4} = 64 \times -\frac{1}{4}\]

Answer 3

@waterineyes is it 1/16?

Answer 4

\[8 \times 8 \times -\frac{1}{4}\]

Answer 5

?

Answer 6

well what if I write it this way

\[-\frac{ 8 \times 8}{4} =\]

Answer 7

-16?

Answer 8

correct

Answer 9

so is that the final answer?

Answer 10

thanks

Answer 11

yes,,, provided you question was correctly written