A committee of 5 parents is to be established from a group of 6 men and 4 women. a) Find how many different committees can be formed.
See the combinations can be: 1 man 4 women 2 men 3 women 3 men 2 women 4 men 1 woman 5 men and no woman.. Now apply the combinations...
For One man and 4 women: 6C1*(4C4) solve this first..
6C1 x 4C4 = 6
Why it can't be 10C5 ? No other conditions are given.
No It is not true..
hmmm?
Are that getting you the answer @JayDS
nope, I am 5 off.
The original answer is??
Do you know how we cannot choose 10C5 ??
(6C1x4C4) + (6C2 x 4C3) + (6C3 x 4C2) + (6C4 x 4C1) + 1 =247
nope.
original answer is 252.
What is the original answer??
Okay now let me try..
kk
Have you tried 10C5??
@waterineyes : Cant it be straight way 10C5 ??
I think no..
If you want to choose all are women then how can you choose 5 women from 4 ??
actually it works for some reason 10C5=252
maybe the textbook answer is wrong?
May be I am wrong..
Oh sorry.. I think I got it thanks Ganpat..
as it only says, committee of 5 parents.. without specifying any fix ratio of male and female.. So i think !! :)
please explain in easy terms lol.
Yes @JayDS I am wrong in that.. Sorry..
See 10C5 will give you the 5 members taken at one time from the 10 members..
Here no condition is given that atleast or atmost words come in the question..
okok.
An ice-cream vendor offers chocolate, strawberry and vanilla ice-creams with one, two or three scoops. How many different ice-creams are possible? (Assume that you cannot choose two scoops of the same flavour for any one one ice-cream.)
What the question says is committee of 5 is to be formed out of 6men and 4 women.. They have not specified , whether minimum 2 women and 3 men shd be selected or anything as such.. So it can be simply 10c5...
yep k, I'll give the medal to @ganpat for figuring it out.
i guess, it shd be = 3 * 3! ?? @waterineyes : what say ??
the answer is actually 7. I tried 3C1+3C2+3C3 and it works but I want to know why is it 3C2 and 3C3?
one scoop - 3 two scoops - 3*2 3 scoopts - 1
add them
that's confusing lol.
ok
answer me this assume : you have 3 flavors of ice creams in the menu. how many ways you can make the order for one ice cream
simply 3C1
one scoop of ice cream u meant?
yes
next you want to take choose a ice cream with 2 scoops - you have to choose 2 flavors from the available 3. how many ways you cam choose 2 flavors from 3 ?
3C2 right ?
yep but there is the possibility of choosing the same flavours.
yes thats why its 3C2 combination implies all choices are different
like Chocolate & chocolate or strawberry & strawberry or vanilla & vanilla.
really?
those wont come in 3C2 those will come in 3*3
yes
ok, so when will it just be 3x3?
when you dont bother about all scoops being different. its 3 * 3 ways u can choose
btw, 3*3*3 forms 3 scoop ice creams
ok, but I've already given somebody else the medal so I have another question that I will create in a new post that you can help me with,
sorry.
lol you gave me so many medals before... sodont bother :))
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