Question

i need to put this in the form of linear differential equation (the one with the D's)

\[y = 2e^x \cos 3x\]

Answer 1

i think \[m = 1 \pm 3i\]

Answer 2

where is ur equation? lol ; i cant see

Answer 3

\[y = 2e^x \cos x\]
that's the equation lol

Answer 4

i need to make it look like (D^2 -2D +10)y= 0

Answer 5

\( m=1\pm 3i \) and \( (m-1)^2=-9 \) so \( m^2-2m+10=0 \)

Answer 6

what did you do?

Answer 7

ohh you transposed

Answer 8

then squared huh

Answer 9

yep

Answer 10

I have a question: what is 'm'?

Answer 11

@mukushla

Answer 12

A link would be helpful too if you are too bored to type a reply!

Answer 13

http://en.wikipedia.org/wiki/Characteristic_equation_(calculus)