Question

solve 4^(x + 7) = 6^(x-1)

Answer 1

\(4^{x+7}=6^{x-1}\)
\(4^7\cdot4^{x}=\frac16\cdot6^{x}\)
\(\left(\frac46\right)^{x}=\frac1{6\cdot4^7}\)
\(x=\log_\frac46\frac1{6\cdot4^7}\)