Question

Please help, Algebra 2!

Answer 1

Where is algebra 2??

Answer 2

Use the substitution method to solve the following system of equations.

4x – y = 3
7x – 9y = –2

(1, 1)

(6, –3)

(6, 1)

(1, –3)

Answer 3

the choicees are in parenthesis

Answer 4

Can you find y from first equation??

Answer 5

it could be 4(2) - 5= 3 but how do i know what x is?

Answer 6

Wait it is not the right way to that..

Answer 7

i dont know :/

Answer 8

See:


4x - y = 3

So

Subtract 4x both the sides:

-y = 3 - 4x

So now multiply by (-1):

y = -3 + 4x

or y = 4x - 3

Answer 9

so x is -1?

Answer 10

Sorry x = 1 is right..

Answer 11

so is it (1,-3) ?

Answer 12

So now you got : y = 4x - 3

Put this value in the second equation in place of y:

7x – 9y = –2

7x - 9(4x-3) = -2

7x - 36x + 27 = -2

-29x = -29

x = 1

Answer 13

What is : 4 - 3 = ??

Answer 14

1

Answer 15

so this is y..

Answer 16

Which option is this??

Answer 17

so its 1,1

Answer 18

Absolutely..

Answer 19

thankyou very much :)