Question

.Choose the equation of the line passing through the point (4, -2) and perpendicular to y = 1/3x - 7.

y = -3x - 14

y = 3x - 10

y = -3x + 10

y = 3x + 14

Answer 1

Firstly find the slope of perpendicular line:

y = 1/3x - 7

So coefficient of x will give you slope : 1/3

So the slope of other line will be negative reciprocal of 1/3 that is (-3)


So use:

\[\large y - y_1 = m(x-x_1)\]

So:

\[y+2 = -3(x-4)\]

So:

y = -3x + 12 - 2

y = -3x + 10