Question

(x+6)/(x^2-4x-21) + (x+2)/(x^2-6x-27)

Answer 1

I have (x+6)/(x-7)(x+4) + (x+2)/(x-9)(x+3) but not sure what to do next

Answer 2

(x+6)/(x-7)(x+4) sure of this one ?:

Answer 3

i meant (x-7)(x+3)

Answer 4

now, all you can do is to add them ! after "putting" them at the same denominator :)

Answer 5

what about the numerator

Answer 6

by multiplying the first "the numerator and the denominator by (x-9)
and the second "the numerator and the denominator by (x-7)
do this and see what you'll get !

Answer 7

all i got was codes when you wrote that

Answer 8

\[\frac{(x+6)(x-9)}{(x-7)(x+3)(x-9)}+\frac{(x+2)(x-7)}{(x-7)(x+3)(x-9)}\]
now can you add them ?!

Answer 9

what do you mean add them?

Answer 10

like foil?

Answer 11

\[\frac{a}{d}+\frac{b}{d}=???\]

Answer 12

no i dont get it

Answer 13

:'( ! you don't know that \[\frac{a}{d}+\frac{b}{d}=\frac{a+b}{d}\] ??

Answer 14

i understand but i dont know how to do it with (x+6)(x-9) + (x-2)(x-7)

Answer 15

so ! we agree that what you typed is equal to \[\frac{(x+6)(x-9)+(x+2)(x-7)}{(x-7)(x+3)(x-9)}\] ???

Answer 16

yes

Answer 17

so ! can you calculate (x+6)(x-9)+(x+2)(x-7) ?!

Answer 18

no i already said that i dont know how to

Answer 19

(x+6)(x-9)=(x)(x)+(x)(-9)+(6)(x)+(6)(-9)=x^2-3x-54
can you do the same for (x+2)(x-7) ?

Answer 20

yeah i asked if you just foil and yous aid no

Answer 21

but i get it now...thank you!

Answer 22

I didn't say no :) !

Answer 23

you're welcome ! anytime !