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OpenStudy (anonymous):
Given a regular square pyramid with RS = 6 and PX = 4, find the following measure. PS = ? Hint: The answer has a 4 in it.
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OpenStudy (anonymous):
OpenStudy (allank):
RS=6 thus XY=YS=3 XS = sqrt(XY^2+YS^2) = sqrt(18) PS = sqrt(PX^2+XS^2) = sqrt(16+18) = sqrt(34)
OpenStudy (anonymous):
okay, sorry i was writing it down, but thanks a bunch :)
OpenStudy (allank):
You're welcome ;)
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