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OpenStudy (anonymous):
(x/(5x+5)=(2x-3)/(x+1) - (4x)/(5x+5)
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OpenStudy (anonymous):
Can we factor out 5 from both (5x+5)?
OpenStudy (anonymous):
yeah 5(x+1)
OpenStudy (anonymous):
great.Do you observe something which all denominators contain?
OpenStudy (anonymous):
x+1
OpenStudy (anonymous):
Yes.Now cancel it out as all denominators contain it.
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OpenStudy (anonymous):
okay
OpenStudy (anonymous):
Now multiply 5 by 2x-3 so that the whole right hand side term contain 5 as a denominator.
OpenStudy (anonymous):
okayso x=3
OpenStudy (anonymous):
yes you got it...
OpenStudy (anonymous):
thank you!
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