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Rewrite y = x2 + 14x + 29 in general form using the complete the square method
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(x+14/2)^2 +29 - (14/2)^2
so, you take the first term +( half second term/2)^2 - (half second term/2)^2 + c
so it would be (x+78)-49??
no. You need to keep it in the squared form. So, you have (x+7)^2 +29-49. The simplified answer is then (x+7)^2 -20
nvm..it would be (x+78)(x-78)...right
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if you foil it out.
oh okay...i get it now
just remember the formula, (x + B/2)^2 +c-(B/2)^2
thankyou for ur help
no problem. These gave me such problems before. Have a good day.
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you too :)
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