Question

What is a solution for the following system of equations?
y=x^2
y=-4x+12

thank you.

Answer 1

Put the value of y in eq 2, i.e.,
\[\LARGE{y=-4x+12}\]\[\LARGE{x^2=-4x+12}\]\[\LARGE{\implies x^2+4x-12=0}\]

Answer 2

Now solve it by Quadratic Formula:)\[\Huge{\color{green}{-b \pm \sqrt{b^2-4ac}\over2a}}\]Can u do it now??

Answer 3

Okay, Give me a moment to try this

Answer 4

a=1, b=4, c=-12.

Answer 5

Okay. So
\[-4\sqrt{4}^2-4(1)(-12) \]

Answer 6

then divide by 4?

Answer 7

The answer i got was -4

Answer 8

i have to eat dinner. ill be right back!

Answer 9

Answer will be:-
\[\LARGE{-4\pm \sqrt{4^2-4(1)(-12)}\over2(1)}\]

Answer 10

ok