Can someone show me what I'm doing wrong please?
Given a regular square pyramid with RS = 6 and PX = 4, find the following measure.

PY = ? (My Answer: PY = 10)

Question

Can someone show me what I'm doing wrong please?
Given a regular square pyramid with RS = 6 and PX = 4, find the following measure.

PY = ?                                 (My Answer: PY = 10)

anonymous · Answer

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anonymous · Answer

The answer is 5.
Use Pythagoras theorem.
Hypotenuse is what you want.
The other sides are PX and RS/2.
Solve for PY and have your answer.

anonymous · Answer

okay, i solved the problem the way you said, and i got 5 too, so thanks a bunch! :)