Question

find an equation for the tangent line to the curve x^(1/2)+ y^(1/2)= 3 at the point (4,1)

Answer 1

\[y=(3-\sqrt{x})^2=x-6\sqrt{x}+9\]differentiate with respect to x to get the equation of the slope of the tangent line. Then use point slope for of a line to get the equation of the tangent line at (4,1).