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Calculate the number of even 3 digit positive integers with no repeated digits by finding the number of such integers that have: 1) unit digits 0 2) and non zero digits Verify your answer by comparing the number of odd 3 digit postive integers with no repeated digits with the total number of 3 digit positive integers with no repeated digits
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1) ....-...-0 so (8)*9 2) ...-...-... (8)*(9)*(9) because (1)and(2) can never be at the same time ! so the total is (9)*9*8+8*9 a number is odd if only its unit digits is odd ...-...-odd (8).(9).(5) obviously 8*9*5<9*9*8+8*9
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