Question

Quadrilateral ABCD has vertices at A(-2,-1) . B (-4,-7) C(-9,-3) D(-8,-6) . It is reflected across the x-axis. What are the new coordinates? Explain.

Answer 1

@ash2326 .. i asked this earlier but i dont think the awsner i got is correct . can u help ?

Answer 2

i got ; A(-2,1) B(-4,7) C(-9,3) D(-8,6). Because you do the opposite number of the "y " .

Answer 3

Hint: Use graph paper

Answer 4

i am

Answer 5

Okay, next plot the points

Answer 6

i did

Answer 7

Okay, next find out how far each point is from the x axis.

Answer 8

Start with the point closest to the x-axis

Answer 9

a(-2,1) is 2 away from the x axis and one over.

Answer 10

so 2.-1 ?? for a

Answer 11

Whatever the distance each point is from the x-axis, its reflected point will be the same distance. Vertical distance only. the "one over" isn't a vertical distance.

Answer 12

omg ,

Answer 13

so confusing

Answer 14

wait!

Answer 15

Actually, you just need to figure out how to count distance from the x-axis. When they say x-axis, you must first identify what "x-axis" is.

Answer 16

cant you just do ; To reflect across the X axis, simply multiply all the Y coordinates by -1.

Answer 17

Vertical distance means "up and down" distance

Answer 18

Okay, just wait...

Answer 19

wait.

Answer 20

Don't try anything yet, just listen

Answer 21

Sigh

Answer 22

imsorry ...

Answer 23

Okay here's what to do.

1. Put your pencil on the x-axis directly beneath the first point you want to find the distance of.

2. Then draw a line from the x-axis to that point.

3. Count the number of units from the x-axis to that point.

4. The number of units represents the distance from the x-axis to the point

5. The reflected point will be the equal and opposite distance from the x-axis.

Answer 24

I hope that makes sense.

Answer 25

It does!

Answer 26

i got ...

Answer 27

A(-2,1) B(-4,7) C(-9,3) D(-8,6

Answer 28

Yeah, that's right. I realize that you already had it. lol

Answer 29

Lol i was double checking :) thanks!

Answer 30

Good job