Question

PLEASE HELP!!! Fill in the missing term so that the quadratic equation has a graph that opens up, with a vertex of
(– 2, – 16), and x intercepts at x = -6 and x = 2.

y = x2 + 4x − __

Answer 1

substitute the values

-16= (-2)^2 + 4(-2) - c
-16 = 4 - 8 - c
c = 4 - 8 +16
c = 12

y = x2 + 4x - 12

Answer 2

thank you so much! i thought the answer was -20