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what is the answer for the 17th question?
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pls answer
x^3 + 1/x^3 = (x + 1/x)(x^2 + x*1/x + 1/x^2) = 7 ( 7^2 - 2 + 1) = 7*48
x^2+1/x^2 = (x+1/x)^2 - 2
idid nt understand a thing
a^3+b^3 = (a+b)(a^2-ab+b^2) x^3 + 1/x^3 = (x + 1/x)(x^2 - x*1/x + 1/x^2)
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7*47
how is 1/x^3 =b^3????
(1/x)^3 = 1/x^3
\[(x)^{3}+(1/x)^{3}= (x+1/x) (x ^{2}-x \times1/x+1/x ^{2})\]
\[= 7( ???????)\]
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x^2+1/x^2 = (x+1/x)^2 - 2
7^2 - 2
cn u do it the equation way...itll be more helpful
\[ x^2+1/x^2 = (x+1/x)^2 - 2 = 49 -2 = 47\]
thank u
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-x/1/x = -1
7*46
wait 1more doubt |dw:1343204914752:dw|
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