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2*7-4^2/2(12-7)
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= 14 - 16/2*5
\[\frac{2 \times(7-4)^2}{2(12-7)}\]\[\frac{2(3)^2}{2(5)}\]\[\frac{2 \times9}{10}\]\[\frac{9}{5}\]
hmm - the question is a bit ambiguous - open to interpretation i've assumed a different setup to jitesh
if jiesh's is right then 7-4 should have been in parentheses
the 7-4 is nt in parentheses
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it looks just like jitesh but the 7-4 is not in parentheses
aaahh ok is this correct then |dw:1343217439965:dw|
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