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log(x-3)=2?
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First change it to exponential form. \[10^2 = x - 3\]Can you solve for x?
\[\log (x-3) = 2\] it is implicit when given this kind of thing that the base is 10 so \[\log_{10} (x-3) = 2\] now change to exponential \[10^2 = x - 3\] expand \[100 = x - 3\] add 3 to both sides \[100 + 3 = x\]
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