Question

log[3](x^2-8x)=2, 3 is a base.

Answer 1

->Exponential Form
->Quadratic formula

Answer 2

\[log_3(x^2-8x) = 2\]
\[log_ay=x => a^{x} = y\]
\[=> 3^{2} = x^2-8x\]

Answer 3

@Mimi_x3 Use \log, it's prettier :D

Answer 4

lol too lazy to :P

Answer 5

:P

Answer 6

then use the quadratic formula as zepp stated; then solve for \(x\)