Question

If a ball dropped from a tower reaches the ground after 3.5 seconds, what is the height of the tower?
Given: g = -9.8 meters/second^2

Answer 1

u have initial velocity u = 0, time t = 3.5 sec, acceleration a = 9.8m/s^2.
u need to find the height of the tower = distance covered in time t = s.
use s = ut + 1/2 at^2

Answer 2

thanks

Answer 3

np!