Question

The sum of three consecutive odd integers is 33.

What is the first integer?

7
9
11
13

Answer 1

HELP PLEASE

Answer 2

let the first number is x, then
x + (x+2) + (x+4) = 33

Answer 3

(2n-1)+(2n+1)+(2n+3) = 33
2n - 1 =?

Answer 4

which 1 do i go by

Answer 5

find the value of n ... then find the value of 2n-1
your three consecutive integers is 2n-1, 2n+1, and 2n+3

Answer 6

7

Answer 7

RadEn methods works too ... but when you are dealing with odd number it's customary to write 2n+1 or 2n-1.

Answer 8

oh, sorry .. i was wrong make the model maths to solve the problem

Answer 9

what is the answer yall are confusing me

Answer 10

http://www.wolframalpha.com/input/?i=%282n-1%29%2B%282n%2B1%29%2B%282n%2B3%29+%3D+33
2n-1=10-1=9

so the numbers are 9,11, 13

Answer 11

yea, that's right 9+11+13 = 33 hehe..