Question

Could someone show me the steps on how to solve cube 3 to the square root 27/y^6

Answer 1

\[\LARGE \sqrt[3]{\frac{27}{y^6}}\]

Answer 2

Use the property of \[\LARGE \sqrt[3]\frac{a}{b}=\frac{\sqrt[3]a}{\sqrt[3]b}\]

Answer 3

Can you try?

Answer 4

@jolliffbrett Can you try to apply this property of your question?

Answer 5

i came up with 3/y^2 is that correct

Answer 6

Correct! :D

Answer 7

Thanks,how about the square root of 9x^6/64y^3